Math Question: The length of a side of a rhombus is 8 and the length of the shorter diagonal is 6 a) find the length of the other diagonal to the nearest tenth b) find the area of the rhombus to the nearest tenth

If the shorter diagonal is 6, then half that diagonal is 3. The half diagonal, the side, and half the other diagonal form a right triangle with side 3,x,8, 8 being the hypotenuse. From Pythagoras we have: 8^2=3^2+x^2 64=9+x^2 64-9=x^2 55=x^2 sqrt(55)~= 7.416 =7.4 to the nearest tenth So 14.8 to the nearest tenth for the entire diagonal (not just the half diagonal that makes on side of this triangle). There's several formulas for the area of a rhombus, but the easiest here will be "half the product of the diagonals." (p*q)/2 (14.8*6)/2=14.8*3=44.4 Which is already to the nearest tenth.
Answered On 05/27/2020 15:17