A bag contains a mixture of almonds, walnuts, and cashews. There is an equal quantity of each nut. If a nut is chosen randomly out of the bag, what is the probability that an almond will be selected or that a cashew will be selected?

2/3 since there are equal numbers. You add the number of almonds and cashews and divide by the amount of all the nuts (x+x)/3x = 2x/3x = 2/3
Answered On 06/26/2019 19:13

So if all the nuts have the same amount in the bag, there will be a 1/3 chance for each of them. For example: If there is 1 of each in the bag, there's a 1 of 3 chance of getting any of them. But the problem states almonds or cashews, so that means you add the probability of both of the nuts. So almond probability is 1/3 and cashew probability is 1/3, so the probability of getting an almond or cashew is 2/3. Hope this helped :)
Answered On 07/01/2019 16:00