A bag contains a mixture of almonds, walnuts, and cashews. There is an equal quantity of each nut. If a nut is chosen randomly out of the bag, what is the probability that an almond will be selected or that a cashew will be selected?
Asked By cammie On 06/25/2019 15:33
Answers
2/3 since there are equal numbers. You add the number of almonds and cashews and divide by the amount of all the nuts (x+x)/3x = 2x/3x = 2/3
Answered On 06/26/2019 19:13
Answered On 06/26/2019 19:13
So if all the nuts have the same amount in the bag, there will be a 1/3 chance for each of them.
For example: If there is 1 of each in the bag, there's a 1 of 3 chance of getting any of them.
But the problem states almonds or cashews, so that means you add the probability of both of the nuts.
So almond probability is 1/3 and cashew probability is 1/3, so the probability of getting an almond or cashew is 2/3.
Hope this helped :)
Answered On 07/01/2019 16:00
Answered On 07/01/2019 16:00
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