Math Question: Solve (D^2-3D+2)y =x(x+4) and show that its general solution is given by y=Ae^x + Be^2x +(x^2/2) + (7x/2) + (19/4) My work : auxiliary eqn , m^2 - 3m + 2= 0 m=1 , m=2 Reduced eqn : yn = Ae^x + Be^2x P.I. = 1/f(D)*F(x) = (1/(D^2-3D+2))*(x(x+4)) P.I. = [(x^2+4x) + ( (1/2)*( 2- 3(2x) - 3(4) ) ) + (1/4)(9*2) ) P.I. = x^2 + (4x/2) - (6x/4) - (5/2) + (18/4) P.I. =(x^2/2) + x + 8/4 General solution : y= Ae^x + Be^2x + (x^2/2) + x + 8/4 Could anyone point out my mistakes?

Asked By AshLey On 12/04/2019 10:18